2 years ago

Can anybody please answer question 6

Mathematics

1 answer:

rewona [7]2 years ago

7 0

Answer:

2 to 12

Step-by-step explanation:

its not that hard

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$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
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\end{array}\\\\
-----------------------------\\\\
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\\\\\\
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\begin{cases}
p=6\\
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solve for "k", to find k or the "constant of variation"

then plug k's value back to $\bf p=\cfrac{k}{(q-2)^3}$

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is

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