Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
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-Brainly support team (Klara academic DEPT.)Spam words mean team is having trouble determining the question CONTACT For support.
Answer:
The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25. The second useful rule is the Sum Rule.
There are 8 tens in the number 1,384.
Each digit in the number has an equivalent value based on its placement in the number.
1,384 where:
1 is in the thousands value
3 is in the hundreds value
8 is in the tens value
4 is in the ones value
The extended form of 1,384 is:
1 x 1000 + 3 x 100 + 8 x 10 + 4 x 1 = 1,384
1,000 + 300 + 80 + 4 = 1,384
8 x 10 = 80 ; shows that there are 8 10s in the number with a product of 80.
Answer:
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Step-by-step explanation:
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