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2 years ago

Solve the problem.

Mathematics

1 answer:

zmey [24]2 years ago

6 0

Answer:

the percent of increase is 24%

Step-by-step explanation:

The percent of increase in general could be calculate as:

$\frac{Vf - Vi}{Vi} *100$

where Vf is final value and Vi is initial value.

From the question we know that Vi is equal to 25 and Vf is equal to 31. Replacing this values on the equation we get:

$\frac{31-25}{25} *100=24%$

That's mean that at second attempt the percent of increase is 24%, taking into account that at the first attempt a student get 25 questions correct.

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Which expression is equivalent to 4√147 A. 28√3 B. 12√7 C. 3√7

grin007 [14]

Answer:

(A) 28 squared 3

Step-by-step explanation:

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2 years ago

Z varies directly with q. when z=2,q=1 . find a formula connecting z and q z=???

Lostsunrise [7]

Answer:

$z = \frac{q}{2}$

Step-by-step explanation:

$z \infty q$

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2 years ago

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In the year 2,000 there were 8.7 deaths per 1000 residents in the united States.if there were 281,421,906 residents in the U.S.

jolli1 [7]

32,347,345.5 people died in the year 200

6 0

2 years ago

Not the best at this! Can someone please help me ?!

umka2103 [35]

Answer:

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Step-by-step explanation:

5 0

2 years ago

We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty

maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let X = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable X is, p = 0.697.

A random sample of n = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable X follows a Binomial distribution with parameters n = 50 and p = 0.697.

The probability mass function of a Binomial random variable X is:

$P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...$

(1)

Compute the expected value of X as follows:

$E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9$

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56$

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of X ≥ 45 as follows:

P (X ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

$=\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006$

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. p < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0

2 years ago