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2 years ago

5

The next model of a sports car will cost 13.6% more than the current model. The current model costs $58,000 . How much will the

price increase in dollars? What will be the price of the next model?
Increase price:

Price of next model:

1 answer:

Anettt [7]2 years ago

7 0

Answer:

increase price: $7,888

price of next model:65,888

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If y varies directly as x and y=288 when x=16 determine the value of y when x-13

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Y = kx is the direct variation equation
Substitute the x and y that are given to find k then write your new equation in terms of y with the k.

288 = k(16) divide by 16 to find k
18 = k
Now write the new equation
y = 18x

y = 18(13) or y = 18(-13) I'm not sure by what you have typed if that is supposed to be and equal sign or a negative.
y = 234 OR y = -234

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3 years ago

Some parts of California are particularly earthquake- prone. Suppose that in one metropolitan area, 25% of all homeowners are in

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Answer:

a. Binomial random variable (n=4, p=0.25)

b. Attached.

c. X=1

Step-by-step explanation:

This can be modeled as a binomial random variable, with parameters n=4 (size of the sample) and p=0.25 (proportion of homeowners that are insured against earthquake damage).

a. The probability that X=k homeowners, from the sample of 4, have eartquake insurance is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}\\\\\\P(x=k) = \dbinom{4}{k} 0.25^{0}\cdot0.75^{4}$

The sample space for X is {0,1,2,3,4}

The associated probabilties are:

$P(x=0) = \dbinom{4}{0} p^{0}(1-p)^{4}=1*1*0.3164=0.3164\\\\\\P(x=1) = \dbinom{4}{1} p^{1}(1-p)^{3}=4*0.25*0.4219=0.4219\\\\\\P(x=2) = \dbinom{4}{2} p^{2}(1-p)^{2}=6*0.0625*0.5625=0.2109\\\\\\P(x=3) = \dbinom{4}{3} p^{3}(1-p)^{1}=4*0.0156*0.75=0.0469\\\\\\P(x=4) = \dbinom{4}{4} p^{4}(1-p)^{0}=1*0.0039*1=0.0039\\\\\\$

b. The histogram is attached.

c. The most likely value for X is the expected value for X (E(X)).

Is calculated as:

$E(X)=np=4\cdot0.25=1$

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Step-by-step explanation:

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