B = -16
m = (-15-(-16))/18-0 = 1/18
y= 1/18x - 16
SO we need 5 numbers that equal to 20, with 5 being the middle number, and ones being the most used number so
1 1 5 x y
According to this, x and y must equal 13 and both be bigger then 5. Because we can rule out every other number, x and y must be 6 and 7.
Your 5 numbers are 1, 1, 5, 6, 7.
Answer:
84? Not sure but pretty sure
Step-by-step explanation:
In a straight line, the word can only be spelled on the diagonals, and there are only two diagonals in each direction that have 2 O's.
If 90° and reflex turns are allowed, then the number substantially increases.
Corner R: can only go to the adjacent diagonal O, and from there to one other O, then to any of the 3 M's, for a total of 3 paths.
2nd R from the left: can go to either of two O's, one of which is the same corner O as above. So it has the same 3 paths. The center O can go to any of 4 Os that are adjacent to an M, for a total of 10 more paths. That's 13 paths from the 2nd R.
Middle R can go the three O's on the adjacent row, so can access the three paths available from each corner O along with the 10 paths available from the center O, for a total of 16 paths.
Then paths accessible from the top row of R's are 3 +10 +16 +10 +3 = 42 paths. There are two such rows of R's so a total of 84 paths.
80÷12= 6 2/3
12×12×12×12×12×12=72
so 12 goes into 80 evenly 6 times, but there is a remainder so you have to include it
80-72=8
so that leaves you with 8/12 which is 2/3 when simplified
now you have 6 + 2/3 = 6 2/3
C. For every decrease of one chore completed, one hour was spent on the internet.
