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3 years ago

What do I put in the boxes

Mathematics

1 answer:

miv72 [106K]3 years ago

3 0

X = 0 1 64 49 6
y = 0 1 8,-8 7,-7 - $\sqrt{6}$

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(-(-2)4), (minus(minus two)power four)=

docker41 [41]

-(-2)^4 = 16

The - sign multiplies inside the bracket to a positive, 2^4 = 16

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4 years ago

Someone help me please

svp [43]

Subtract like terms.

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3 years ago

Each leg of a 45°-45°-90° triangle measures

Semmy [17]

Answer:

the hypotenuse is 14

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4 years ago

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The fish tank in aquatic science has a length of 15 inches, a width of 10 inches, and a height of 20 inches. The water in

pantera1 [17]

Answer:

900

Step-by-step explanation:

10*15*6=900

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3 years ago

Which of the following functions are solutions of the differential equation y'' + y = 3 sin x? (select all that apply)

DiKsa [7]

Answer:

Step-by-step explanation:

We must compute the derivatives and check if the equation is satisfied.

A. $y'=(3\sin x)'=3\cos x$ . Differentiate again to get $y''=(3\cos x)'=-3\sin x$ , then $y''+y=-3\sin x+3\sin x=0\neq 3\sin x$ so this choice of y doesn't solve the equation.

B. $y'=3\sin x+3x\cos x-5\cosx +5x\sin x=(5x+3)\sin x+(3x-5)\cos x$ and $y''=5\sin x+(5x+3)\cos x+3\cos x-(3x-5)\sin x=(10-3x)\sin x+(5x+6)\cos x$ , then $y''+y=10\sin x+6\cos x\neq 3\sin x$ so y is not a solution

C. $y'=\frac{-3}{2}\cos x+\frac{3}{2}x\sin x$ hence $y''=\frac{3}{2}\sin x+\frac{3}{2}\sin x+\frac{3}{2}x\cos x=3\sin x+\frac{3}{2}x\cos x$ . Then $y''+y=3\sin x+\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\sin x$ so y is a solution.

D. $y'=-3\sin x$ and $y''=-3\cos x$ , then $y''+y=0$ thus y isn't a solution

E. $y'=\frac{3}{2}\sin x+\frac{3}{2}x\cos x$ hence $y''=\frac{3}{2}\cos x+\frac{3}{2}\cos x-\frac{3}{2}x\sin x=3\cos x-\frac{3}{2}x\cos x$ . Then $y''+y=3\cos x-\frac{3}{2}x\cos x-\frac{3}{2}x\cos x=3\cos x\neq 3\sin x$ then y is not a solution.

3 0

3 years ago