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kompoz [17]
3 years ago
15

Help, show work please (NO LINKS)​

Mathematics
1 answer:
Reptile [31]3 years ago
4 0
3.29/18= about 0.18
5.59/28= about 0.2

the best buy is option a!
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Are these expectations equivalent? Explain why or why not 42+35 7(6+5)<br><br> HELP PLEASE
const2013 [10]

\frac{42}{35} :\frac{6}{5}

7\left(\frac{6}{5}\right)=\frac{42}{5}

They are not equivalent.

6/5= 1.2

42/5= 8.4

3 0
3 years ago
Double somme help please
Lady_Fox [76]

Answer:

looks like a nazi symbol

Step-by-step explanation:

7 0
2 years ago
Please help me with this.
vodka [1.7K]

The rate of change would be 300 bacteria per minute at 0.1 minutes past 1 PM

<h3>The exponential function of the bacteria</h3>

The given parameters are:

Initial, a = 20

At 30 minutes, Value = 500

An exponential function is represented as:

y = ab^t

Where a is the initial value.

So, we have:

y = 20b^t

After 30 minutes, we have:

20b^30 = 500

Divide both sides by 20

b^30 = 25

Take the 30th root of both sides

b = 1.11

Substitute b = 1.11 in y = 20b^t

y = 20(1.11)^t

Hence, the exponential model is y = 20(1.11)^t

<h3>Minutes to reach 11,000</h3>

This means that:

y = 11,000

So, we have:

20(1.11)^t = 11000

Divide both sides by 20

1.11^t = 550

Take the logarithm of both sides

tlog(1.1) = log(550)

Divide both sides by log(1.1)

t = 66

Hence, the population would reach 11,000 after 66 minutes

<h3>The population at 2PM</h3>

This means that:

t = 60 i.e. 60 minutes after 1PM

So, we have:

y = 20(1.11)^60

Evaluate

y = 10481

Hence, the population at 2PM is 10481

<h3>The rate of change at 2PM</h3>

In (c), we have:

y = 10481 ------ population at 2PM is 10481

t = 60

The rate of change is calculated as:

Rate = 10481/60

Evaluate

Rate = 174.68

Hence, the rate of change at 2PM is 174.68 bacteria per minute.

<h3>When the rate would be 300 bacteria per minute?</h3>

The rate of change is calculated as:

Rate = Population/Time

So, we have:

y/t = 300

This gives

y = 300t

Substitute y = 300t in y = 20(1.11)^t

300t = 20(1.11)^t

Divide both sides by 20

15t = (1.11)^t

Using a graphing calculator, we have:

t = 0.1

Hence, the rate would be 300 bacteria per minute at 0.1 minutes past 1 PM

Read more about exponential functions at:

brainly.com/question/11464095

#SPJ1

7 0
2 years ago
An escalator lifts people to the second floor of a​ building,34ft above the first floor. The escalator rises at a 30 degree angl
Anit [1.1K]

Answer:

68 ft

I've attached the Trignometric ratio theory as well

<em>hope you understood </em><em>:</em><em>)</em>

4 0
3 years ago
Help please will mark brainliest!
Nat2105 [25]

Answer:

Option B. Cosec θ = –5/3

Option C. Cot θ = 4/3

Option D. Cos θ = –4/5

Step-by-step explanation:

From the question given above, the following data were obtained:

Tan θ = 3/4

θ is in 3rd quadrant

Recall

Tan θ = Opposite / Adjacent

Tan θ = 3/4 = Opposite / Adjacent

Thus,

Opposite = 3

Adjacent = 4

Next, we shall determine the Hypothenus. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus =?

Hypo² = Opp² + Adj²

Hypo² = 3² + 4²

Hypo² = 9 + 16

Hypo² = 25

Take the square root of both side

Hypo = √25

Hypothenus = 5

Recall:

In the 3rd quadant, only Tan is positive.

Therefore,

Hypothenus = –5

Finally, we shall determine Sine θ, Cos θ, Cot θ and Cosec θ to determine which option is correct. This can be obtained as follow:

Opposite = 3

Adjacent = 4

Hypothenus = –5

Sine θ = Opposite / Hypothenus

Sine θ = 3/–5

Sine θ = –3/5

Cos θ = Adjacent / Hypothenus

Cos θ = 4/–5

Cos θ = –4/5

Cot θ = 1/ Tan θ

Tan θ = 3/4

Cot θ = 1 ÷ 3/4

Invert

Cot θ = 1 × 4/3

Cot θ = 4/3

Cosec θ = 1/ Sine θ

Sine θ = –3/5

Cosec θ = 1 ÷ –3/5

Invert

Cosec θ = 1 × –5/3

Cosec θ = –5/3

SUMMARY

Sine θ = –3/5

Cos θ = –4/5

Tan θ = 3/4

Cot θ = 4/3

Cosec θ = –5/3

Therefore, option B, C and D gives the correct answer to the question.

5 0
3 years ago
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