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Vikki [24]
3 years ago
15

Find the value of 2a -t for a = 7 and t = 10.

Mathematics
1 answer:
Zina [86]3 years ago
4 0

Answer

27=10

Step-by-step explanation:

i dont know tbh

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Ken has a toy chest with hot wheels cars. He has 6 camaros, 2 Lamborghinis, 4 corvettes, 8 Ferraris and 12 mustangs. Ken wants t
ipn [44]
Lamborghini=
fraction = 2/32
Decimal = 0.0625
Percentage= 6.25%

Corvette=
Fraction= 4/32
Decimal=0.125
Percentage=12.5%



Explanation:


Since the problem says “lamborghini OR corvette” you need to add the probability amount of both cars together. There are 2 lamborghinis and 4 corvettes, so 2+4=6. Now, put this number over the total amount of all cars. 6+2+4+8+12=32. So, the probability will be 6/32 which simplifies to 3/16. In decimal form this is .1875, and in percent form this is 18.75% (move the decimal 2 places to the right)
5 0
2 years ago
What are the steps to solve this problem?<br><br> 0.0000000009 ÷ 0.0003<br><br> Show your work
Ivanshal [37]

Step-by-step explanation:

0.0003÷0.0000000009=

333,333.33333333

4 0
3 years ago
jack ran 1.5 kilometers on the treadmill, then walked 475 meters before running another 2.5 kilometers how many kilometers did j
qaws [65]
We need first consider what data we have available:
a = run 1.5km
b = then run 2.3km
c = walk 475m
x = a + b + c = how many km he done on treadmill
before we go anywhere, we need to unify the units, we need to change meters to fraction of kilometers, kilo meant 1000, therefore:
1km = 1000m
475m / 1000m = 0.475km
now we can substitute:
x = a + b + c = 1.5km + 2.3km + 0.475km = 4.275km
we can round that up to first decimal point and then:
4.275km = 4.3km
answer is then:
jack done on the treadmill 4.275km or rounded up 4.3km
3 0
3 years ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
Pls help with this question
Sedaia [141]
So the 3 2 minutes of the game
5 0
3 years ago
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