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Mariulka [41]
3 years ago
9

Elena tiene 50 pilas de monedas

Mathematics
1 answer:
nadezda [96]3 years ago
8 0
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Can u help with this asap​
Zolol [24]

Answer:

B

Step-by-step explanation:

-7x<-21

x<-3

7 0
4 years ago
If fan is fully open, what is the approximate area of the fan? Answer choices are attached.
scoundrel [369]

Answer:

Option B. 78.8\ in^2

Step-by-step explanation:

step 1

Find the area of a circle with radius 8.5 inches

The area of a circle is equal to

A=\pi r^{2}

substitute

A=\pi (8.5)^{2}

A=72.25\pi\ in^2

step 2

Find put the approximate area of the fan

we know that

The area of complete circle subtends a central angle of 360 degrees

so

using proportion

Find the area that correspond a central angle of  125 degrees

\frac{72.25\pi}{360^o}=\frac{x}{125^o}\\\\x=72.25\pi(125^o)/360^o\\\\x=25.09\pi\ in^2

assume

\pi =3.14

25.09(3.14)=78.8\ in^2

8 0
3 years ago
For a fundraiser, a KIPP New Jersey is selling raffle tickets for $2 each
Finger [1]
Yes! If the raffle tickets are $2 and Amari supposedly purchased 8, that would make the total money for raffle tickets $16. Then if you take the 4 snacks for $1.50 each that would be $6.
16+6=22
7 0
3 years ago
2x + 2 = 5x – 10<br> answer plssssss
kow [346]

Answer:

Brainliest

Step-by-step explanation:

2x+2 = 5x-10

3x=12

x=4

5 0
3 years ago
Read 2 more answers
The formula for a buffer solution contains 1.24% w/v of boric acid. How many milli-liters of a 5% w/v boric acid solution should
Oksanka [162]

Answer: 248mL

Step-by-step explanation:

Given:

Concentration of buffer solution Cs = 1.24%w/v of boric acid

Concentration of boric acid solution Cb = 5 % w/v boric acid

For 1 liter of buffer solution, the weight of boric acid needed is:

mb = 1 × 1.24 = 1.24 unit weight

mb = Cb × Vb .....1

Cb = concentration of boric acid solution.

Vb = volume of boric acid solution needed.

mb = weight of boric acid needed.

From equation 1.

Vb = mb/Cb

Vb = 1.24/5

Vb = 0.248L

Vb = 248mL

4 0
3 years ago
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