Question

What is the force on a 1000 kg elevator that is falling freely at 9.8 m/sec 2?

Answer 1

Answer:

Force, F = 9800 Newton

Explanation:

Given the following data:

Mass = 1000 kg

Acceleration, a = 9.8 m/s²

To find the force;

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

$F = ma$

Where;

• F represents force.

• m represents the mass of an object.

• a represents acceleration.

Substituting into the equation, we have;

$F = 1000 * 9.8$

F = 9800 Newton.