Answer:
The length of the rectangle is 11 inch and its width is 8 inch.
Step-by-step explanation:
Given:
Rectangle 
and rectangle 
.
Let the width of the rectangle be 'x' inch.
Its length = '(x+3)' inch
Area of the rectangle = 
⇒
= 
Now for rectangle its width is decreased by 1 inch and length is doubled,the area 
will increased by 66 sq-inch.
So,
According to the question.
⇒ Area of rectangle with width '(x-1)' and length '2(x+3)'='(2x+6)' .
⇒ 
Plugging the values of 
in terms of .
⇒ 
Plugging = into the equation.
⇒ 
⇒ 
⇒ 
⇒ 
Now using quadratic formula we can find the value of 'x'.
Quadratic formula, (x)= 
x= -9 and x= 8
Discarding the negative value.
Our width = 'x' = 8 inches.
So the length of the rectangle = 11 inches and width of the rectangle = 8 inches.
Answer:
x=4
Step-by-step explanation:
-x+4=2x-8
4=2x-(-x)-8
4=2x+x-8
4=3x-8
3x=4+8
3x=12
x=12/3
x=4
Answer:
I'm guessing what your asking is this equation or expression in fraction form? If so, then it would be 16/4 which equals 4.
Step-by-step explanation:
Answer: We have c = 3 and d = -2
Step-by-step explanation:
We want to solve the equation:
6200.07 = 6.2x10^c + 7x10^d
First, we can separate the left number into two pieces:
6200.07 = 6200 + 0.07 = 6.2x10^c + 7x10^d
Now we can solve it as:
6200 = 6.2x10^c
6200/6.2 = 10^c
1000 = 10^c
now we can use that if y = a^x, then ln(y)/ln(a) = x
here we have:
c = ln(1000)/ln(10) = 3
and
0.07 = 7x10^d
0.07/7 = 10^d
0.01 = 10^d
d = ln(0.01)/ln(10) = -2
