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kap26 [50]
3 years ago
7

what is the independent and dependent variable...School Raffle, number of tickets sold and money collected

Mathematics
2 answers:
Elanso [62]3 years ago
6 0
Dependent: number of tickets sold and money collected Independent: school Raffle
Marrrta [24]3 years ago
5 0
Independent is the thing that changes
dependent is the thing being tested
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The graphs of two linear equations ax + by = c and bx - ay = c, where a, b, c are all not equal to zero.
marin [14]
Let us find the slopes of the two lines

ax+by=c, slope m1 = -a/b

bx-ay=c, slope m2 = b/a

m1*m2 = (-a/b)(b/a) = -1

Therefore the two lines are perpendicular so the answer is D
4 0
3 years ago
PLEASEEEEEEE HELP ME!
kodGreya [7K]

Answer:

option D

congruent

Step-by-step explanation:

A)

A chord of a circle is a straight line segment whose endpoints both lie on the circle.

B)

parallel lines NEVER meet at a single point

C)

the segments are perpendicular to the circle

D)

Tangent segments to a circle from the same external point are congruent.

As,

if we make a right angle triangle from these tangent, these both will share same central leg as well as same other leg, radius.

6 0
3 years ago
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Why do many people think it is better to not receive a refund from the irs at the end of the year?
Monica [59]
Because the more years you go without receiving it the more it comes out to after you cash out. It starts to add up year by year :)

5 0
3 years ago
PLease help me answer this.
Natasha2012 [34]

Answer:

1093.96

Step-by-step explanation:

900(1+.05)⁴=1093.955625

7 0
3 years ago
Suppose the force acting on a column that helps to support a building is a normally distributed random variable X with mean valu
Sauron [17]

Answer:

(1) 0.4207

(2) 0.7799

Step-by-step explanation:

Given,

Mean value,

\mu = 15.0

Standard deviation,

\sigma = 1.25

(1) P(X ≥ 17.5) = 1 - P( X ≤ 17.5)

= 1- P(\frac{x-\mu}{\sigma} \leq \frac{17.5-\mu}{\sigma})

=1-P(z\leq \frac{17.5 - 15}{1.25})

=1-P(z\leq \frac{2.5}{1.25})

=1-P(z\leq 2)

=1- 0.5793   ( By using z-score table )

= 0.4207

(2) P(14 ≤ X ≤ 18) = P(X ≤ 18) - P(X ≤ 14)

=P(z\leq \frac{18 - 15}{1.25}) - P(z\leq \frac{14 - 15}{1.25})

=P(z\leq \frac{3}{1.25}) - P(z\leq -\frac{1}{1.25})

=P(z\leq 2.4) - P(z\leq -0.8)

= 0.9918 - 0.2119

= 0.7799

8 0
3 years ago
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