Ask question

Ask question

All categories

3 years ago

15

two sides of an equilateral triangle measure (2y+3) units and (y^2 -5) units. if the perimeter of the triangle is 33 units, what

's the value of y?

2 answers:

eimsori [14]3 years ago

3 0

The answer would be -17y.

ANTONII [103]3 years ago

3 0

Multiply 2y+3 by three to make the sides of the triangle. Then set that equal to 33. This should give you y.

3(2y+3)=6y+9. 6y+9=33 6y=24 y=4

You might be interested in

Cual es el resultado? 3x-2=

MrMuchimi

Reinforces 5tttxes el

7 0

3 years ago

Read 2 more answers

2. Jill works for Fast Food Inc. and earns $332 per week and is paid bi-weekly. How much is deducted

adoni [48]

Answer:

Social Security: $9.63

Step-by-step explanation:

5 0

2 years ago

I don't know what is the rule I know that this graph is a exponential decay table I don't know how to find the rule can anyone h

jarptica [38.1K]

Answer is c just in place of x subst x values and your y will come out

6 0

3 years ago

If you run a marathon of 26 1/5 miles in a time of 5 4/5 how far do you run in 1 hour<br><br>pls

alisha [4.7K]

First let's make both the miles and the hours ran improper fractions:

$26+\frac{1}{5}=\frac{131}{5}\\ 5+\frac{4}{5}=\frac{29}{5}$

So, to find our miles per hour, we have to divide the miles by the hours to get: $\frac{\frac{131}{5}\text{miles}}{\frac{29}{5}\text{hours}}=\frac{131\text{miles}}{29\text{hours}} \\ \text{ Now we have to divide the top and the bottom by 29 to get our miles per hour so: }\\ \frac{\frac{131}{29}}{\text{hour}} \approx \frac{4.52 \text{miles}}{\text{hour}}$

8 0

3 years ago

A runner runs around a circular track. He completes one lap at a time of t = 269 s at a constant speed of v = 4.6 m/s. What is t

AURORKA [14]

Answer:

$\boxed{\text{197 m}}$

Step-by-step explanation:

The formula relating distance (d), speed (s), and time (t) is

d = st

1. Calculate the distance

d = 269 s × 4.6 m·s⁻¹ = 1240 m

2.Calculate the track radius

The distance travelled is the circumference of a circle

$\begin{array}{rcl}C & = & 2 \pi r\\1240 & = & 2 \pi r\\\\r & = & \dfrac{1240}{2 \pi }\\\\& = & 197\\\end{array}\\\text{The radius of the track is }\boxed{\textbf{197 m}}$

5 0

3 years ago