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worty [1.4K]
3 years ago
7

On every three hamburgers that McDonald's makes, they use 9 pickles write the ratio in simplest form.How many pickles would they

use on 100 burgers( show work)
Mathematics
2 answers:
VashaNatasha [74]3 years ago
5 0

Answer: They would use 300 pickles for 100 hamburgers.


Step-by-step explanation:

Given: McDonald's use 9 pickles for 3 hamburgers

⇒Ratio of hamburger to pickles=3:9

Ratio in simplest from 3:9=\frac{3}{9}=\frac{1}{3}=1:3

⇒McDonald's use pickles for 1 hamburger.

Now Number of pickles for 100 hamburgers= 100×3=300

Therefore, They would use 300 pickles for 100 hamburgers.

murzikaleks [220]3 years ago
4 0
Hamburgers/pickles
3/9 x/100 cross multiply to get 300=9xx
Now you have an algebraic equation.
divide 300 by 9, and you'll have your answer which is 100 pickles.

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Find the sum of the geometric sequence. (1 point) 1, one divided by two, one divided by four, one divided by eight, one divided
Firlakuza [10]
GP = 1/2 , 1/4 , 1/8 , 1/16
1st) the common ratio is (1/4 : 1/2 ) = 1/2, so r =1/2
2nd) the sum of a GP is:

S= a(1-rⁿ)/(1-r)

S=(1/2).[1-(1/2)⁴]/(1-1/2) = 15/16

6 0
3 years ago
Read 2 more answers
Could someone help me and explain?
ExtremeBDS [4]

Answer:

  • length 3 in
  • width 2 in

Step-by-step explanation:

Since none of the answer choices match the drawing of the gardener, we assume the question is referring to the drawing of the partner.

The gardener's drawing is 1/4 of actual size. So, in terms of the gardener's drawing, actual size is ...

  gardener's drawing = (1/4)actual size

  actual size = 4(gardener's drawing)

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The partner's drawing is 1/20 of actual size, so is ...

  partner's drawing = actual size/20 = (4(gardener's drawing))/20

  partner's drawing = (4/20)(gardener's drawing)

  partner's drawing = (gardener's drawing)/5

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Then the {length, width} of the partner's drawing are ...

  partner's drawing {length, width} = {15 in, 10 in}/5 = {3 in, 2 in}

The partner's drawing has a length of 3 inches and a width of 2 inches.

6 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
How to solve all of this
photoshop1234 [79]
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Move diagonally to the circle with the radius of 6.2.

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Move upwards to the circle with the radius of 10.5

third circle: 2πr = 2(3.14)(10.5) = 66

Move right to the circle with the diameter of 16.6

Fourth circle: πd = (3.14)(16.6) = 52.2

Move down to the circle with the diameter of 7.7

fifth circle: πd = (3.14)(7.7) = 24.2

Move down to the circle with the diameter of 50

Sixth circle: πd = (3.14)(50) = 157.1

Move left to the circle with the radius of 11.8

Seventh circle: 2πr = 2(3.14)(11.8) = 74.1

Move down to the circle with the radius of 38

Eight circle: 2πr = 2(3.14)(38) = 238.8

Move right to the circle with the diameter of 1.1

ninth circle: πd = (3.14)(1.1) = 3.5

Move right to the circle with the radius of 14.8

10th circle = 2πr = 2(3.14)(14.8) = 93

Move up to the end.

Hope this helps :) 
7 0
3 years ago
a foreman must order enough sod to cover a dirt area 36 feet wide by 28 feet long. each piece of sod is 3 feet long and 12 inche
Andrews [41]

If we divide the area we have to cover by the area of a piece, we will get the number of pieces needed:

n=\dfrac{\text{dirt area}}{\text{piece area}}=\dfrac{36\times 28}{3\times 12} = \dfrac{36\times 28}{36}=28

3 0
2 years ago
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