Answer: the number of minutes of long distance call that one can make is lesser than or equal to 12 minutes.
Step-by-step explanation:
Let x represent the number of minutes of long distance call that one makes.
The first three minutes of a call cost $2.10. After that, each additional minute or portion of a minute of that call cost $0.45. This means that if x minutes of long distance call is made, the total cost would be
2.10 + 0.45(x - 3)
Therefore, the inequality to find the number of minutes one can call long distance for $6.15 is expressed as
2.10 + 0.45(x - 3) ≤ 6.15
2.10 + 0.45x - 1.35 ≤ 6.15
0.75 + 0.45x ≤ 6.15
0.45x ≤ 6.15 - 0.75
0.45x ≤ 5.4
x ≤ 5.4/0.45
x ≤ 12
Answer:
how to solve 2x+2y=2 , -4x+4y=12
this is solving equations using substitution .... i have ALOT more but i juss dnt get this stuff
2x + 2y = 2 -4x + 4y = 12
x + y = 1
x = 1 - y
-4x + 4y = 12
-4(1 - y) + 4y = 12
(-4 + 4y) + 4y = 12
-4 + 8y = 12
8y = 16
y = 2
2x + 2y = 2
2x + 2(2) = 2
2x + 4 = 2
2x = -2
x = -1
Check.
-4x + 4y = 12
-4(-1) + 4(2) = 12
4 + 8 = 12
Answer: x = -1 and y = 2
Step-by-step explanation:
Answer: She makes $550
Step-by-step explanation:
This is because to find the answer you do 10000t imes 5.5%
And 5.5% is 0.055
So you do 10000 times 0.055
Which is 550
Answer:
627200LJ
Step-by-step explanation:
Height of box=5 m
Side of square base=4 m
Volume of rectangular box=
Using the formula
Volume of rectangular box=
Density of material=
We know that

Using the formula
Mass of rectangular box=
Gravity=
Weight of rectangular box,F=
Let L be the vertical distance traveled by box
Total work done =
Therefore,total work done against gravity =
=627200 L J
Hence, the box requires work against gravity=627200LJ
I'm pretty sure the answer is 12.