Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
C
Explanation:
Metamorphosis is the action of moths and butterflies changing into a different form.
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Answer:
The correct answer is - Both move with constant speed.
Explanation:
If an object moves in a particular way that it covers the same distance at the same times the speed considered as constant suppose if two objects a and b both travel 10 m and 20 m respectively and the time they take in travel are 2 and 4 seconds respectively than we can say they both have a constant speed.
The relation between the variables x,t, and v is
x=v.t
If V is constant which is the speed we get a straight line x-t in the graph.
By the given information we can say that both objects A and B are traveling at a constant speed.
Answer:
A.) Cell A
Explanation:
This is bc it has the smallest space.
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Answer:
I believe the answer is d
