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2 years ago

Can you guys help me with this question?

Mathematics

1 answer:

Rasek [7]2 years ago

8 0

Answer:

it represents 10 stars in the galaxies

Step-by-step explanation:

10 to the power of 12 would be 1,000,000,000,000, 10 to the power of 11 would be 100,000,000,000, and those two number divided equals simply 10.

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Graph this equation: x - 2y = 6

Nady [450]

Answer:

The image below shows the equation x - 2y = 6 being graphed.

Hope this helps! :)

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3 years ago

Please help, i need to figure out the price of bag, not proportional ($)

Lilit [14]

Answer:

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Step-by-step explanation:

5 0

3 years ago

I WILL GIVE BRAINLIEST!! I really need help with this question.

Annette [7]

Answer: x = 70, y = 110, z = 85

Step-by-step explanation:

If BE = CD, then using corresponding angles (are equal), x = 70

If x = 70, then 70+y = 180 (angles on a straight line)

y = 110

And z = 85 (corresponding angles again): angle ABE = angle ACD

7 0

3 years ago

Read 2 more answers

Ana drew a map of the Panama Canal in the scale Ana used for the map 4 centimeters represents 20 kilometers what is the scale fa

Ganezh [65]

Answer:

Step-by-step explanation:

5 0

3 years ago

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$

Topic: AP Calculus BC (Calculus I + II)

Unit: Parametric Integration

Book: College Calculus 10e

4 0

2 years ago