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Bess [88]
3 years ago
11

Write an expression for the length 7mm and it’s width 62mm for the rectangle

Mathematics
1 answer:
4vir4ik [10]3 years ago
3 0
The expression for the length would be L = w + 7
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Simplify the expression 35e^9/5e^8
erastovalidia [21]

\frac{35e {}^{9} }{5 {e}^{8} }  \ \\  \\   \frac{7e {}^{9} }{e {}^{8} }  \\  \\  \\  = 7e

Step By Step Explanation:

  • Reduce: Reduce the fraction with 5
  • Simplify: Simplify the expression

Alternate Forms:

  • 19.02797

<h3>☆彡Hanna</h3>
5 0
3 years ago
Table 1<br> Table 2<br> Table 3<br> Table 4. Please help fast
Natasha2012 [34]
Table 2 heheheheheehehehehheheheheehheheheheheheheehehehehhehehehehhehehehehehe
6 0
3 years ago
HELP WILL GIVE BRAINLIEST BUT MUST ANSWER ASAP
ser-zykov [4K]

Answer:a and point b

i hope i helped u

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Add an intersection the red light times normally distributed by the mean of three minutes and a standard deviation of .25 minute
Soloha48 [4]

95% of red lights last between 2.5 and 3.5 minutes.

<u>Step-by-step explanation:</u>

In this case,

  • The mean M is 3 and
  • The standard deviation SD is given as 0.25

Assume the bell shaped graph of normal distribution,

The center of the graph is mean which is 3 minutes.

We move one space to the right side of mean ⇒ M + SD

⇒ 3+0.25 = 3.25 minutes.

Again we move one more space to the right of mean ⇒ M + 2SD

⇒ 3 + (0.25×2) = 3.5 minutes.

Similarly,

Move one space to the left side of mean ⇒ M - SD

⇒ 3-0.25 = 2.75 minutes.

Again we move one more space to the left of mean ⇒ M - 2SD

⇒ 3 - (0.25×2) =2.5 minutes.

The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.

Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)

Therefore, the percent of  red lights that last between 2.5 and 3.5 minutes is 95%

8 0
4 years ago
Rephrase in contrapositive form:
miv72 [106K]

Step-by-step explanation:

Consider the provided information.

For the condition statement p \rightarrow q or equivalent "If p then q"

The rule for Contrapositive is: Negative both statements and interchange them. \sim q \rightarrow \sim p

Part (A) If you are taller than 6 ft, then it is unpleasant for you to travel in economy class.

Here p is "you are taller than 6 ft, and q is "it is unpleasant for you to travel in economy class".

It is given that Your contrapositive must not contain explicit references to negation. Assume that the negation of "unpleasant" is "pleasant".

Contrapositive: If it is pleasant for you to travel in economy class then you are not taller than 6 ft then.

Part (B) "If x ≥ 0 and y ≥ 0 then xy ≥ 0" where x, y are real numbers.

Here p is "xy≥ 0, and q is "x ≥ 0 and y ≥ 0"

The negative of xy≥ 0 is xy<0, x ≥ 0 is x<0 and y ≥ 0 is y<0.

Remember negative means opposite.

Contrapositive: If xy < 0 then x<0 and y<0.

8 0
3 years ago
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