If 5 consecutive integers is 205,
then a + b + c + d + e = 205
but also, each integer is separated by a difference of 1
⇒ a + (a + 1) + (a + 2) + (a + 3) + (a + 4) = 205
⇒ 5a + 10 = 205
⇒ 5a = 195
⇒ a = 39
∴ third term = 39 + 2
= 41
Answer:
B
Step-by-step explanation:
68 is not a prime number. The prime factorization of 68 would be 2 x 2 x 17.
Answer:
C
Step-by-step explanation:
If you look closely.. You can see that one is longer than the other
