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Nitella [24]
2 years ago
9

If g(x)=4x^2-16 were shifted 5 units to the right and 2 down hat would the new equation be

Mathematics
1 answer:
nadezda [96]2 years ago
7 0

Answer:

This is the answer

Step-by-step explanation:

This is the solution, hope it helps

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Where do I put the parentheses in 21-8-6=7
Sliva [168]

Answer:

around 21-8 so the equation would look like this (21-8)-6=7

Step-by-step explanation:

you do this because if u put the parentheses around 8-6 you would get 21- (8-6)= 19 because 21 - 2 = 19 so you have to put them around 21-8 to get the right answer

7 0
3 years ago
Read 2 more answers
Need your help ASAP please help
eduard

His average is 86 so it is below 90.  to get his average i just added all of his grades up to get 517 and then I divided 517 by 6 because thats how many grades he has and I got 86.

On the Grade row in the table it would go 83, 94, 79, 90, 96, 75 in order

The Above/Below 90 row would go -7, 4, 11, 7, -6, -3 in order

Lamont needs to get a 99 on his next test to have an average of exactly 90.


I HOPE THIS HELPED! PLEASE RATE ME AND MAKE MY ANSWER MOST BRAINLIEST!!

5 0
3 years ago
HELPPP circle theorems
Serggg [28]

Answer:

56 degrees.

Step-by-step explanation:

We need the measure of < g.

The triangle formed by the 2 tangents and the chord is isosceles, because 2 tangents from a point  outside a circle are of equal length (by the Two Tangents theorem).

Also one of the base angles are equal to 62 degrees ( by The Tangent Chord theorem). In fact both base angles are 62 degrees because the triangles an isosceles.

So measure of angle g = 180 - 2(62)

= 56 degrees.


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3 years ago
Get brainliest SOlve correctly
Minchanka [31]

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8 0
3 years ago
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Assume that the population proportion is 0.56. Compute the standard error of the proportion, σp, for sample sizes of 100, 200, 5
Aliun [14]

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049

When sample size is n = 200

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035

When sample size is n = 500

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022

When sample size is n = 1000

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016

4 0
3 years ago
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