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2 years ago

Choose the correct order of events in the Kreb's cycle:

Biology

2 answers:

Ierofanga [76]2 years ago

7 0

Pyruvate is split, citric acid is formed, coenzyme A is added

Zigmanuir [339]2 years ago

7 0

The right answer is Pyruvate is split, citric acid is formed, coenzyme A is added

*Decarboxylation of pyruvate, is the reaction catalyzed by pyruvate dehydrogenase complex linking glycolysis to the Krebs cycle by converting pyruvate to acetyl-CoA.

*Citrate synthase condenses oxaloacetate and acetyl-CoA into citrate with release of coenzyme A. A transient intermediate, citroyl-CoA, is formed. The thioester linkage of acetyl-CoA is a high-potential hydrolysis bond. The coupling of the hydrolase and synthase activities makes the synthesis reaction thermodynamically possible.

*In the oxidative decarboxylation of α-ketoglutarate, the α-ketoglutarate dehydrogenase complex catalyzes the oxidative decarboxylation of α-ketoglutarate to succinyl-CoA with production of NADH + H + and evolution of CO2. It is a reaction similar to that converting pyruvate to acetyl-CoA catalyzed by the pyruvate dehydrogenase complex.

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Where would a pictograph not appear in your experiment outline

Vinvika [58]

The answer is observations

3 0

3 years ago

Which letter in the graph indicates a time of decreasing growth?

Novosadov [1.4K]

Answer:

It would be A

Explanation:

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3 years ago

When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

From this cross the expected ratios are:

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3>Chi square test</h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

The observed frequencies were:

34 Red
76 Pink
40 White

Total 150

The expected frequencies for our null hypothesis are:

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

3 years ago

Which final discovery about cells led to the development of the cell theory?

xxMikexx [17]

Answer:

The answer is A

By the late 1830s, botanist Matthias Schleiden and zoologist Theodor Schwann were studying tissues and proposed the unified cell theory. The unified cell theory states that: all living things are composed of one or more cells; the cell is the basic unit of life; and new cells arise from existing cells.

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3 years ago

Read 2 more answers

Which statement is true about photosynthesis?

aleksley [76]

Answer:

during photosynthesis energy from the Sun is stored in chemical bonds of a glucose molecule

5 0

3 years ago