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olga2289 [7]
2 years ago
8

!solve this! 3x + 70 − 7x ≥ 18

Mathematics
1 answer:
UNO [17]2 years ago
8 0

Answer:

3x + 70 − 7x ≥ 18

Step 1: Simplify both sides of the inequality.

−4x + 70 ≥ 18

Step 2: Subtract 70 from both sides.

−4x + 70 − 70 ≥ 18 − 70

−4x ≥ −52

Step 3: Divide both sides by -4.

−4x /−4  ≥  −52 /−4

x ≤ 13

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erik [133]

Answer:

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

Step-by-step explanation:

we have

y=-x^{2} +2x+10 ----> equation A

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The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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in this problem we have

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x=\frac{-1\pm\sqrt{1^{2}-4(-1)(8)}} {2(-1)}

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x=\frac{-1+\sqrt{33}} {-2}  -----> x=\frac{1-\sqrt{33}} {2}  

x=\frac{-1-\sqrt{33}} {-2}  -----> x=\frac{1+\sqrt{33}} {2}  

<em>Find the values of y</em>

For x=\frac{1-\sqrt{33}} {2}  

y=x+2

y=\frac{1-\sqrt{33}} {2}+2  ---->y=\frac{5-\sqrt{33}} {2}  

For x=\frac{1+\sqrt{33}} {2}  

y=x+2

y=\frac{1+\sqrt{33}} {2}+2  ---->y=\frac{5+\sqrt{33}} {2}  

therefore

The solutions of the system of equations are the points

(\frac{1-\sqrt{33}} {2},\frac{5-\sqrt{33}} {2})  

(\frac{1+\sqrt{33}} {2},\frac{5+\sqrt{33}} {2})  

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