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MariettaO [177]
2 years ago
15

Andrea, a 65.0 kg sprinter, starts a race with an acceleration of 3.700 m/s2. If she accelerates at that rate for 12.50 m and th

en maintains that velocity for the remainder of a 100.00 m dash, what will her time (in s) be for the race?
Mathematics
1 answer:
astra-53 [7]2 years ago
5 0

Step-by-step explanation:

Below is an attachment containing the solution

You might be interested in
I need help with math -4+a=15
MrMuchimi

Note the equal sign. What you do to one side, you do to the other. Isolate the a.

Add 4 to both sides

a- 4 (+4) = 15 (+4)

a = 15 + 4

a = 19

19 is your answer for a

hope this helps

5 0
2 years ago
Read 2 more answers
Help! I don't understand this
Murljashka [212]

The area of your circle is about 530.93 m

The diameter of your circle is 26 m, just multiply your radius by 2

The circumference of the circle is about 81.68


The equation to finding the area is

pi x r x 2

3.14 times 13 times 2

The equation to finding the diameter

r x 2

radius times 2

The equation for finding circumference

pi x d

3.14 times 26

Let me know if im wrong, otherwise I want brainliest, PLEASE!!

8 0
3 years ago
27. TEMPERATURE Eleven Fahrenheit temperatures are shown on a map during
ser-zykov [4K]

Answer:

5 negative numbers

Step-by-step explanation:

-5 -4 -3 -2 -1 0 1 2 3 4 5

1  2  3  4  5 6 7 8 9 10 11

6 0
3 years ago
What’s the sequence?
Troyanec [42]

Answer:

see explanation

Step-by-step explanation:

Note that the difference between consecutive terms is - 8

To obtain the next term in the sequence subtract 8 from the previous term.

next term = 56 - 8 = 48

The sequence is 72, 64, 56, 48

3 0
3 years ago
What are all of the real roots of the following polynomial? f(x) x^4-24x^2-25
Greeley [361]

<u>Answer:</u>

x = ±5

<u>Step-by-step explanation:</u>

We are given the following polynomial function and we are to find all of its real roots:

x^4-24x^2-25

Let y=x^2 so we can now write it as:

y^2-24y-25

Factorizing it to get:

(y^2+y)+(-25y-25)

y\left(y+1\right)-25\left(y+1\right)

\left ( y + 1 \right ) \left ( y - 2 5 \right)

Substitute back y=x^2 to get:

\left ( x^2 + 1 \right ) \left ( x^2 - 25 \right )

\left ( x^2 + 1 \right ) \left ( x + 5 \right ) \left ( x - 5 \right )

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.

3 0
3 years ago
Read 2 more answers
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