Answer:
0.79
Step-by-step explanation:
Here,
Let X be the event that the flights depart on time
Let Y be the event that flights arrive on time
So,
X∩Y will denote the event that the flights departing on time also arrive on time.
Let P be the probability
P(X∩Y)=0.65
And
P(X)=0.82
We have to find P((Y│X)
We know that
P((Y│X)=P(X∩Y)/P(X) )
=0.65/0.82
=0.79
So the probability that a flight that departs on schedule also arrives on schedule is: 0.79
Answer: option D
Step-by-step explanation:
Remember the cosine identity:

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

Now you can substitute values into
and then reduce the fraction.
THerefore you get:
By definition we have to:
A set has under an operation if performance of that operation on set members always produces a member of the same set; in this case we also say that the set is closed under the operation.
For this case we have the following polynomials:

Multiplying we have:

The product of two polynomials is also a polynomial.
Answer:
d
is a polynomial
Answer:
5
Step-by-step explanation:
Assuming we want to evaluate |z|, given that, z=4+3i.
Then, by definition of modulus,



Therefore the modulus be of the given complex number is 5 units
20 divided by 4 is 5 so
4$ will be for pay as you go.
5$ will be for regular deal
4+5=9 so the all in one deal is 9$