Hello,
a³-b³=(a-b)(a²+ab+b²)
x^6-27=(x²)³-3³=(x²-3)(x⁴+3x²+9)
Pu 2 together straight up then one above it sideways
From the equation, we can tell that left side of the equation has to be less than or equal to 6 in order for the equation to be true.
So first, let’s try n=0.
Plug it in: 2(0)=0 and since 0 is less than 6, it makes the equation true.
Next, let’s try 1. 2(1)=2. This also makes the equation true.
Next, let’s do n=3. 2(3)=6. So this also makes the equation true.
So the answers are:
n=0 , n=1 , and n=3
Hope this helped and pls mark as brainliest!
~ Luna
As a product it would be length times two plus width times two. as a sum it'd be length + length + width + width
I need help to solve this problems can somebody help me
