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Oksana_A [137]
4 years ago
8

Mary purchased 4 tires by mail order. She paid ​$54.90 per tire plus​ $6.50 per tire for shipping and handling. There is no sale

s​ tax, because the tires were purchased out of state. She also had to pay​ $8.34 per tire for mounting and balancing. At a local​ store, Mary's total for the 4 tires with mounting and balancing would be ​$332 plus 8​% sales tax. How much did Mary save by purchasing the tires through the​ mail? Mary saved ​$ nothing on the purchase of 4 tires.
Mathematics
1 answer:
Alex17521 [72]4 years ago
5 0

Answer:

79.6 dollars saved

Step-by-step explanation:

Mail

4 times 54.90 equals 219.6

4 times 6.50 equals 26

4 times 8.34 equals 33.36

219.6 + 26 + 33.36 = 278.96

Local store

332 times .08 equals 26.56

332 + 26.56 = 358.56

Difference

358.56 - 278.96 = 79.6

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Step-by-step explanation:

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Walt is mixing fruit punch for a party. He combines 1 gallon 2 quarts 3 pints of orange juice, 1 gallon 3 quarts 7 pints of pine
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Need your help now please; the assignment is due tonight and this is the last problem I am having trouble with. The red box is t
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The volume of the region R bounded by the x-axis is: \mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

<h3>What is the volume of the solid (R) on the X-axis?</h3>

If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.

From the given graph:

The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

\mathbf{y-y_1 = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}

here:

  • (x₁, y₁) and (x₂, y₂) are two points on the straight line

Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8)  from the graph, we have:

\mathbf{y-0 = \dfrac{8-0}{2-0}(x-0)}

y = 4x

Now, our region bounded by the three lines are:

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Similarly, the change in polar coordinates is:

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where;

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Therefore;

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  • ⇒ r = 0   to   r = 2/cosθ
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Then:

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^2 (rdr d\theta )}

\mathbf{\iint_R(x^2+y^2)dA = \int ^{tan^{-1}(4)}_{0} \int^{\frac{2}{cos \theta}}_{0} \ r^3 dr d\theta}

Learn more about the determining the volume of solids bounded by region R here:

brainly.com/question/14393123

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