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Tatiana [17]
3 years ago
10

Simplify the expression. 3 - 4 +7 - 4

Mathematics
1 answer:
Tresset [83]3 years ago
4 0
2
3+7=10
-4-4=-8
10-8=2
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The measure of each angles
Aleks [24]
Supplementary angles is when 2 angles add up to 180 degrees.

We will name the smaller angle a and the bigger angle b.

therefore:

b - 172.6 = a

a + b = 180

Now we substitute:

a + b = 180
b - 172.6 + b = 180
2b - 172.6 = 180
2b = 352.6
b = 176.3

To find a:

a + b = 180
a + 176.3 = 180
a = 3.7

Therefore,

angle a = 3.7 degrees
angle b = 176.3 degrees.

Hope it helps and have a great day ahead
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4 years ago
7u-3 <br> Evulate the expersion
jok3333 [9.3K]

Answer:

the answer is 7u-3.

Its in the question

6 0
4 years ago
0.672 nearest hundreth
kolezko [41]
0.67 Since 2 (in the thousandths place) is lower than 5 you round down wich just leaves you with 0.67



3 0
3 years ago
Read 2 more answers
5.346 - 2.289 = ? <br><br> SHOW WORK <br><br> WILL GIVE BRAINLIEST PLEASE
Vlad1618 [11]

Answer:

7.635

Step-by-step explanation:

1 1  

 |5| . |3| |4| |6|

+  |2| . |2| |8| |9|

--------------------------------------------------------

 |7| . |6| |3|

5 0
3 years ago
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Suppose you know the length of a confidence interval of a population mean is 8.4 and the sample mean (x bar) is 10. Find the ​ma
SOVA2 [1]

Answer:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X=10 represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Solution to the problem

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The sample mean \bar X is distributed on this way:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

The margin of error is given by:

ME= z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

The lenght of the interval correspond to:

8.4 = 2ME

ME= \frac{8.4}{2}= 4.2

And since we know the margin of error we can find the limits for the confidence interval:

Lower = 10 -4.2=5.8

Upper = 10 +4.2=14.2

4 0
3 years ago
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