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Pavlova-9 [17]
3 years ago
8

The field inside a running track is made up of a rectangle that is 84.39 m long and 73 m wide, together with a half-circle at ea

ch end. What is the distance around the inside of the track?
Mathematics
1 answer:
ioda3 years ago
6 0

Answer:

The distance around the inside is 199.44 m.

Step-by-step explanation:

Given that,

Length = 84.39 m

Width = 9.76 m

Suppose, all the way around and 73 m wide.

We know that,

Perimeter of half circle is

perimeter = \pi r

We need to calculate the inner radius of the circle

Using formula of radius

r=\dfrac{D}{2}

Put the value into the formula

r=\dfrac{9.76}{2}

r=4.88\ m

We need to calculate the distance around the inside

Using formula of distance

Distance around the inside= two inner perimeter of the circle+two length of rectangle

D=2\pi r+2l

Put the value into the formula

D=2\pi\times4.88+2\times84.39

D=199.44\ m

Hence, The distance around the inside is 199.44 m.

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C. 360 Square meters

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3 years ago
-12 + 8a = -a + 6(2a - 2)
pogonyaev

Answer:

41/6

Step-by-step explanation:

-12+81=-1+6(2a-2)

first distribute:

-12+81=-1+12a-12

combine like terms:

<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>

69=-13+12a

add -13 with 69:

82=12a

divide 82 and 12:

82/12= 41/6

3 0
3 years ago
Read 2 more answers
Joe is 5 years older than Sydney. The sum of their ages is 45. What is Sydney’s age?
sweet-ann [11.9K]

Answer:

20 years old

Step-by-step explanation:

Joe = J

Sydney = S

J = 5 + S

J + S = 45

Substitute

5 + S + S = 45

Add

5 + 2S = 45

Subtract 5 from both sides of the equation

2S = 40

Divide both sides of the equation by 2

S = 20

Sydney is 20 years old

Hope this helps :)

8 0
3 years ago
Which of the following is the quotient of the rational expressions shown
Natali5045456 [20]

Answer:

2x^3/x+5/x-5/ 3x-1

2x^3/ 3x-1

Step-by-step explanation:

we can cut plus and minus sign

3 0
3 years ago
Read 2 more answers
Determine if the following system of equations has no solutions 4x+3y= -8 -8x-6y= 16
cupoosta [38]

\begin{cases} 4x+3y=-8\\\\ -8x-6y=16 \end{cases}~\hspace{10em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

4x+3y=-8\implies 3y=-4x-8\implies y=\cfrac{-4x-8}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3} \\\\[-0.35em] ~\dotfill\\\\ -8x-6y=16\implies -6y=8x+16\implies y=\cfrac{8x+16}{-6} \\\\\\ y=\cfrac{8}{-6}x+\cfrac{16}{-6}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3}

one simple way to tell if both equations do ever meet or have a solution is by checking their slope, notice in this case the slopes are the same for both, meaning the lines are parallel lines, however, notice both equations are really the same, namely the 2nd equation is really the 1st one in disguise.

since both equations are equal, their graph will be of one line pancaked on top of the other, and the solutions is where they meet, hell, they meet everywhere since one is on top of the other, so infinitely many solutions.

3 0
2 years ago
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