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SOVA2 [1]
3 years ago
14

A. 25' B. 10' C. 15' D. 20'

Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

mathematics and I c.15 longer

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QUICKKKK EXPERTS/ACE (and people that know it for sure comment) Brainiest Marked to the first correct answer
Olin [163]
I worked them out separately if I'm correct, then the order is:

x+5y=-2
x+5y=4  These are Inconsistent

y=3x+4
-2x+y=4   These are Consistent independent

3x+y=4
-6x-2y=-8 These are coincident

Inconsistent lines=No solution
Coincident lines=exactly on top of each other
Consistent Independant= Solution, as they cross each other. 

~Hope this helps!

8 0
3 years ago
Find the missing side of each triangle. leave your answers in simplest radical form
dedylja [7]
X^2 = 4^2 - (2√3)^2
x^2 = 16 - 12
x^2 = 4
x = 2

answer
x = 2 cm
7 0
4 years ago
Rationalise the denominator by 6 root 7 minus 1
nikklg [1K]

Answer:

Assuming the numerator was 1.

(6\sqrt{7}+1)/251

Step-by-step explanation:

Assuming the numerator was 1.

1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251

7 0
3 years ago
An urn contains six red balls and four green balls. A sample of seven balls is selected at random.
KIM [24]

There are 10 balls in the Urn Total.

Red: 6

Green: 4

Question One: The probability that five red and two green is selected is likely. (as that is over half for both)

Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.

Question Three: At least four is likely, as  there is more red then green in the Urn.

Hope I helped!

(Mark Brainliest if you can please!)

5 0
3 years ago
HELP ME PLEASE PLEASE
-BARSIC- [3]

Answer:6=C 7=C

Step-by-step explanation:

5 0
3 years ago
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