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DedPeter [7]
3 years ago
5

HELP ME

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

the answer is -64

Step-by-step explanation:

\frac{b}{8}  \leqslant  - 8

b \leqslant ( - 8 \times 8)

b \leqslant  - 64

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Identify the equation of a line with a slope of -4 and a y-<br> intercept of (0, 2).
Bingel [31]

Step-by-step explanation:

We know that the formula for slope is y=mx+b, with m equaling the slope itself and b equaling the y-intercept. Since the slope is -4, we can safely say that the equation starts off as y=-4x.

The y-intercept is (0,2). This means that the x-coordinate is 0 and the y-coordinate is 2, so the y-intercept is 2. Since 2 is being added, the equation is y=-4x+2

Answer:

y=-4x+2

8 0
3 years ago
Find the total surface area of this prism where
bulgar [2K]

Answer:

The total surface area of the prism is 620 cm²

Step-by-step explanation:

The total area of the prism = lateral area + 2 (area of the cross-section)

The lateral area = perimeter of the cross-section × height

∵ The cross-section of the prism is an isosceles triangle

∵ The sides of the triangle are 13 cm, 13 cm, 24 cm

∵ The perimeter of the triangle is the sum of its sides

∴ The perimeter = 13 + 13 + 24 = 50 cm

∴ The perimeter of the cross-section = 50 cm

∵ The height of the prism is 10 cm

→ Use the rule of the lateral area above to find it

∴ The lateral area of the prism = 50 × 10 = 500 cm²

∵ The area of the triangle = \frac{1}{2} × base × height

∵ The base of the triangle = 24 cm

∵ The height of the triangle = 5 cm

∴ The area of the triangle =  \frac{1}{2} × 24 × 5 = 60 cm²

∴ The area of the cross-section = 60 cm²

→ Substitute the lateral area and the area of the cross-section in the rule

  of the total surface area above

∵ The surface area = 500 + 2(60)

∴ The surface area = 500 + 120

∴ The surface area = 620 cm²

∴ The total surface area of the prism is 620 cm²

8 0
3 years ago
HELP ME PLEASE AND JUST GIVE ME THE ANSWER NO EXPLANATION
Arisa [49]

The <em>missing</em> end of the <em>line</em> segment \overline {GH} whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

<h3>How to locate the missing end of a line segment</h3>

In this question we know an end and a midpoint of a <em>line</em> segment. The <em>missing</em> end can be found from the following formula:

M(x, y) = G(x, y) + 0.5 · [H(x, y) - G(x, y)]

M(x, y) = 0.5 · G(x, y) + 0.5 · H(x, y)

0.5 · H(x, y) = M(x, y) - 0.5 · G(x, y)

H(x, y) = 2 · M(x, y) - G(x, y)     (1)

If we know that M(x, y) = (5, 3) and G(x, y) = (1, -5), then the coordinates of the point H are:

H(x, y) = 2 · (5, 3) - (1, -5)

H(x, y) = (10, 6) - (1, -5)

H(x, y) = (9, 11)

The <em>missing</em> end of the <em>line</em> segment \overline {GH} whose midpoint is M(x, y) = (5, 3) and known endpoint is G(x, y) = (1, -5) is the point H(x, y) = (9, 11).

To learn more on line segments: brainly.com/question/25727583

#SPJ1

3 0
2 years ago
Read 2 more answers
Will give extra points and brainliest !! /:
valentinak56 [21]
What’s d? I can’t see it
5 0
3 years ago
Read 2 more answers
Find a slope of the line that contains each pair of points: (-2, -6) and (4, 2)
horsena [70]
The simplest way to do this is to use the formula where

\frac{y(2)-y(1)}{x(2)-x(1)} 

is equal to slope. 

(2--6)/(4--2)= 8/6. 

Hope this helps! 
6 0
3 years ago
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