Since there are no answer choices, there are 3; Point, line and plane.
Answer:
b good luck srro if u am rong
Answer:
Height of flagpole = 571 ft
Step-by-step explanation:
Given:
Angle of elevation to the top of the flagpole is 55° .
Distance from the eyes to the base of flagpole = 400 ft.
To find the height of the flagpole.
Solution:
We can draw the situation as a right triangle as shown below.
In triangle ABC.
∠C= 55°
To find the length AB (height of the flagpole).
Applying trigonometric ratio :
Plugging in values.
Multiplying both sides by 400.
∴ 
Height of flagpole = 571 ft
The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
<h3>What is a circle?</h3>
It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.
Prove algebraically that the straight line with equation x = 2y + 5 is a tangent to the circle with equation x² + y² = 5.
x = 2y + 5 ...1
x² + y² = 5 ...2
If the intersection of the point of the circle and line is one. Then the line is tangent to the circle.
Then from equations 1 and 2, we have
(2y + 5)² + y² = 5
4y² + 25 + 20y + y² - 5 = 0
5y² + 20y + 20 = 0
5y² + 10y + 10y + 20 = 0
5y (y + 2) + 10(y + 2) = 0
(5y + 10)(y + 2) = 0
y = -2, -2
Then the value of y is unique then the value of x will be unique.
The value of x will be
x = 2(-2) + 5
x = -4 + 5
x = 1
The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).
More about the circle link is given below.
brainly.com/question/11833983
#SPJ1
Answer: 4.77
Step-by-step explanation:
40.68-2.52=38.16/8=4.77
