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motikmotik
2 years ago
5

9 cu yd 17 cu in 135

Mathematics
1 answer:
kvasek [131]2 years ago
8 0

Answer:

9 yd^3 (cubic yards)×17 in^3 (cubic inches)×135 = 9.637×10^8 in^6 (inches to the sixth).

Step-by-step explanation:

9 yd^3 (cubic yards)×17 in^3 (cubic inches)×135 = 9.637×10^8 in^6 (inches to the sixth).

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A standard brick is 3.625 inches wide, 2.25 inches high, and 7.625 inches long. How many bricks could be in a pallet of bricks t
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Solution:

Standard brick:

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v=(3.625 in)*(2.25 in)*(7.625 in)

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Pallet of bricks:

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s=(4 feet)*(12 in / 1 feet)→s=48 in

Volume of a pallet of bricks: V=s^3

V=(48 in)^3

V=110,592 in^3

Number of bricks could be in  a pallet: n

n=V/v

n=(110,592 in^3) / (62.19140625 in^3)

n=1,778.252119

n=1,778

6 0
3 years ago
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Answer

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