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jeyben [28]
2 years ago
12

Solve for x: 4 over 5 x + 4 over 3 = 2x x = Write your answer as a fraction in simplest form. Use the "/" symbol for the fractio

n bar. (2 points)
Mathematics
1 answer:
Kipish [7]2 years ago
6 0

Answer:

(5 + √115)/15 or (5 - √115)/15

Step-by-step explanation:

4/5x+4/3 = 2x

Multiply each term by the least common multiple of the denominators (15x)

12 + 20x = 30x²

Move all the terms to the left-hand side.

-30x² + 20x + 12 = 0

Multiply each term by -1

30x² - 20x - 12 = 0

Remove the common factor (2)

15x² - 10x - 6 = 0

Solve by using the quadratic formula

a = 15, b = -10, c = -6

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\= \frac{-(-10)\pm\sqrt{(-10)^2-4(15)(-6)}}{2(15)}\\\\= \frac{10\pm\sqrt{100 + 360}}{30}\\\\= \frac{10\pm\sqrt{460}}{30}\\\\= \frac{10\pm\sqrt{4\times115}}{30}\\\\= \frac{10\pm2\sqrt{115}}{30}\\\\= \mathbf{\frac{5\pm\sqrt{115}}{15}}

x = (5 + √115)/15 or x = (5 - √115)/15

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Trig question above plz plz plz help
alukav5142 [94]
The answers are:
1. B
2.C
7 0
3 years ago
Graph a line that is perpendicular to the line y=-3x + 2 and has a y-intercept of -6.
Fiesta28 [93]

Answer:

Step-by-step explanation:

the line's equation would be

y = 1/3x -6

so just graph a line using this equation

hope this helps <3

6 0
3 years ago
3. Find f[h(a+4)], given the functions below. *
mote1985 [20]

Answer:

C 5a^2 +70a +240

Step-by-step explanation:

We have given these following functions:

f(x) = 5x, g(x) = -2x + 1, h(x) = x^2 + 6x + 8

h(a+4)

This function is:

h(a+4) = (a+4)^2 + 6(a + 4) + 8

h(a+4) = a^2 + 8a + 16 + 6a + 24 + 8

h(a+4) = a^2 + 14a + 48

f[h(a+4)]

f(x) = 5x

Thus

f(h(a+4)) = f(a^2+14a+48) = 5(a^2 + 14a + 48) = 5a^2 + 70a + 240

The correct answer is given by option C.

8 0
3 years ago
To increase or decrease an amount by 30% what single multiplier would you use?
Nataly_w [17]
100%-30%=70%
100%+30%=130%

to decrese by 30%, multiply by 70%
to increase by 30%, multiply by 130%

5 0
3 years ago
Read 2 more answers
Calcula y comprueba las ecuaciones: porfavor alguienn la nesesito pliss a) 2X = 6 b) 10 + Z = 20 c) P + 9 = 11 d) 3X + 8 = + 29
Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

p + 9 - 9 = 11-9

<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

3x+8-8 = 29-8

3x = 21

(3/3)x = 21/3

<u>x = 7</u>

Si remplazamos x en la ecuación original:

3(7) + 8 = 29

21 + 8 = 29

29 = 29

Queda demostrado

e) 2u + 8 = 10

Despejamos u restando 8 en amabos lados de la eacuacion y luego divideindo por 2 en ambos lados de la ecuación.

2u+8-8 = 10-8

2x = 2

(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

2(1) + 8 = 10

2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

5 0
2 years ago
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