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maria [59]
3 years ago
7

snakes rely on behavioral homeostasis to get warmer. what might a snake do in order to increase its body temperature.

Biology
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

They bask in the sun

Explanation:

In other words, they lay on their back to raise their body temperature.

I hope this helps!

nika2105 [10]3 years ago
4 0

Answer:

They could sunbathe

Explanation:

I have a rock python named Franklin and he likes to lie on his rock for about 6 hours a day because it produces heat when the room goes below 75 degrees.

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How are energy inputs and outputs related to chemical reactions
GREYUIT [131]

The large number of areas covered by the chemical energetics can be explained by the different forms in which chemical energy can be released: heat and combustion work, electrical energy in electrochemistry, radiant energy in chemiluminescent systems.

The chemical energy provided by a reaction reflects the energy balance associated with the electronic modifications suffered by the species involved.

From an energy point of view, a chemical reaction between molecules can be schematized in two stages. The first requires a supply of energy and corresponds to the rupture of the bonds of the reactant molecules with release of the atoms which constitute them.

The second releases energy and concerns the creation, by recombination of these atoms, of new bonds entering the structure of the reaction molecules.

As a general rule, the energy released in the second stage is greater than the first. We are talking about exothermic reaction. The difference between these two energies (reaction enthalpy) measures the amount of chemical energy transferred to the external environment.

It is conceivable that this quantity translates, not only the number, but also the strength of the connections involved.

6 0
3 years ago
Which best describes the lysogenic cycle?
Vadim26 [7]

Answer:

The correct answer would be option C.

Lysogenic cycle is one of the two replicating cycles of the virus or bacteriophage.

In this cycle, the genetic material of the virus gets integrated with the genome of the host cell.

The integrated genetic material divides every time the host cell divides and passed on to the daughter cells with each division.

The genetic material of the virus or bacteriophage which gets integrated with the host genome is termed as a prophage.

Thus, the host cell does not get lysed and can reproduce normally.

3 0
3 years ago
Read 2 more answers
You are determining the mass of an object using a triple beam balance. When the pointer is lined up with the zero mark, the ride
Nadusha1986 [10]
The mass of the object is the sum of the masses which shows the riders:
m = 300.00 g + 20.00 g + 8.00 g
m = 328.00 g
Answer:
The mass of the object is 328.00 grams.
3 0
3 years ago
Why is it impossible to understand the totality of the interactions among the organisms in the biosphere?
Aleonysh [2.5K]
In order to understand the totality of the interactions among the organisms in the biosphere, we need to at least understand <span>how the all genes function within organisms and </span>interact<span> with others organism and environment around it.
If we try to make this effort in a world where organisms will keep evolving and environment will keep changing like us, that tasks is impossible to finish.</span>
8 0
3 years ago
Indicate the expected number of Barr bodies in interphase cells of individuals with Klinefelter syndrome; Turner syndrome; and k
madreJ [45]

Answer:

Barr bodies are small bodies that are dark staining bodies that show the inactivated X chromosome, these sex chromatin bodies attach to the membrane of the nucleus of interphase cells.

One less of the total number of X-chromosome (n-1) represents the number of Barr bodies.

Then,

The number of Barr bodies with Klinefelter would be:

Klinefelter (47,XXY): (n-1) = (2-1) = 1 Barr body as here two X chromosome present.

Similarly, for

Turner (45,XO): (n-1) = (1-1) = 0 Barr bodies (X chromosome = 1)

Now, as per the question, the bar bodies for karyotypes given

47,XYY: (n-1) = (1-1) = 0 Barr bodies

47,XXX: (n-1) = (3-1) = 2 Barr bodies

48,XXXX: (n-1) = (4-1) = 3 Barr bodies

7 0
3 years ago
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