1)volume of the pipeline
The pipeline is a cylinder, therefore;
Volume (cylinder)=πr²h
r=radius
h=height of the cylinder
diameter=6 in*(1 ft / 12 in)=0.5 ft
raius=diameter / 2=0.5 ft / 2=0.25 ft.
height=5280 ft
Volume (pipeline)=π(0.25 ft)²(5280 ft)=330π ft³≈1036.73 ft³.
2) we calculate the number of barrel
1 mile of oil in this pipeline is 330π ft³ of oil.
1 barrel of crude------------------5.61 ft³
x----------------------------------330π ft³
x=(1 barrel*330π ft³) / 5.61 ft³=184.8 barrels
3) we calculate the price.
1 barrel---------------$100
184.8 barrels---------- x
x=(184.8 barrels * $100) / 1 barrel=$18,480
Solution: ≈$18,480
Answer:
2 because if x=0 y=1 and 2 is closest so a and b
We turn -5,12 into polar coordinates. It's a Pythagorean Triple so
r = 13 Ф=arctan(-12/5) + 180° ( in the second quadrant )
so -5 = 13 cos Ф, 12 = 13 sin Ф
12 sin x - 5 cos x = 6.5
13 sinФ sin x + 13 cos Ф cos x = 6.5
13 cos(x - Ф) = 6.5
cos(x - Ф) = 1/2
cos(x - Ф) = cos 60°
x - Ф = ± 60° + 360° k integer k
x = Ф ± 60° + 360° k
x = 180° + arctan(-12/5) ± 60° + 360° k
That's the exact answer;
x ≈ 180° - 67.38° ± 60° + 360° k
x ≈ 122.62° ± 60° + 360° k
x ≈ { 62.62°, 182.62°} + 360° k, integer k
Answer:
ang hirap wag nlang hahahahahahahaha
