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Vera_Pavlovna [14]

3 years ago

6

LIKE I ACTUALLY NEED HELP THIS IS LITERAL TESTING NOT NO QUIZ.

1 answer:

Mekhanik [1.2K]3 years ago

4 0

Answer:

2 because if x=0 y=1 and 2 is closest so a and b

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1. Determine if the two expressions are equivalent and explain your reasoning.

Elena-2011 [213]

1. Yes because of the constant and coefficient if you add it. Like the answer is 5m +4.

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4 years ago

Can someone help me with this page?

Roman55 [17]

Sure
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3 years ago

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Select all equations that have two solutions. a x^2=16 b 4x^2=0 c x^2=-16 d 3x+2=14 e x^2-1=24 f (x+8)(x-8)=0

never [62]

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a )

${x}^{2} = 16$

$x = ± \: 4$

Two solutions.

_________________________________

b )

$4 {x}^{2} = 0$

$x = 0$

One solution .

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c )

${x}^{2} = - 16$

$No \: \: solution.$

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d )

$3x + 2 = 14$

$x = 4$

One solution.

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e )

${x}^{2} - 1 = 24$

${x}^{2} = 25$

$x =± \: 5$

Two solutions.

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f )

$(x + 8)(x - 8) = 0$

$x = - 8 \: \: or \: \: x = 8$

Two solutions .

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5 0

3 years ago

A researcher surveyed 220 residents of a city about the number of hours they

olga55 [171]

Answer:

Margin of error of 0.0485 hours.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.025 = 0.975$ , so Z = 1.96.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

In this question:

$\sigma = 0.35, n = 220$

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.96\frac{0.35}{\sqrt{200}}$

$M = 0.0485$

Margin of error of 0.0485 hours.

5 0

3 years ago

Write the equation of the circle with center (2, -3) and a radius of 4.

harkovskaia [24]

C(h,k) radius(r)
C(2,-3) r=4

(x-h)^2 + (y-k)^2 = r^2
(x-2)^2 + (y--3)^2 = 4^2
(x-2)^2 + (y+3)^2 = 16

therefore, the answer is D

8 0

3 years ago

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