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3 years ago

I don't understand this and would appreciate an explanation as well :)

1 answer:

6 0

We want to solve the two equations
$e^{x}=6$
and
$4^{y+3}=3$

First equation.
Take natural log of each side.
$ln(e^{x})=ln(6)\\xln(e)=ln(6)\\
x=ln(6)=1.7918$
Note that ln(e) = 1 by definition.
Answer: x = 1.79 (nearest hundredth)

Second equation.
Take natural log of each side.
$ln(4^{y+3})=ln(3)\\
(y+3)ln(4)=ln(3)\\
y+3= \frac{ln(3)}{ln(4)} =0.7925\\y=0.7925-3=-2.2075$
Answer: y = -2.21 (nearest hundredth)

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The sum of the exterior angles of a pentagon equals 300? True or false

malfutka [58]

25 and then add the decimals they have to be aaddd by the two decimals

3 0

3 years ago

Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t

Blababa [14]

Answer:

x + y = 60 and 1.55x + 1.4y = 88.20 and the solution is x = 32 and y = 28.

Mr. Sanchez’s class earned more money by $10.4.

Step-by-step explanation:

Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each.

Let the number of sold fruit pies is x and bottles of fruit juice is y.

So, from the given condition we can write

x + y = 60 ........ (1)

⇒ 1.4x + 1.4y = 84 ....... (2) and

1.55x + 1.4y = 88.20 ........ (3)

Now, solving equations (2) and (3) we get (1.55 - 1.4)y = (88.2 - 84)

⇒ y = 28

And from equation (1) we get x = 60 - 28 = 32.

Therefore, Mr. Sanchez’s class earned more money. (Answer)

Now, this class have earned $(32 × 1.55 - 28 × 1.4) = $10.4 more. (Answer)

5 0

3 years ago

Read 2 more answers

The Charleston family has less than 500 Dalmatians. There are six times as many Dalmatians with black spots on their right ears

ANEK [815]

Let x be the number of Dalmatians without black spots.
So, x+6x is close to 500, which means x=71.
71*7=497, which is the total number of Dalmatians.
Giving away 6% of this will give you around 467 Dalmatians left.

Answer:467 Dalmatians

7 0

3 years ago

Read 2 more answers

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives <em>q</em> in terms of <em>p</em>, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$