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nika2105 [10]
3 years ago
15

I don't understand this and would appreciate an explanation as well :)

Mathematics
1 answer:
Neporo4naja [7]3 years ago
6 0
We want to solve the two equations
e^{x}=6
and
4^{y+3}=3

First equation.
Take natural log of each side.
ln(e^{x})=ln(6)\\xln(e)=ln(6)\\
x=ln(6)=1.7918
Note that ln(e) = 1 by definition.
Answer: x = 1.79 (nearest hundredth)

Second equation.
Take natural log of each side.
ln(4^{y+3})=ln(3)\\
(y+3)ln(4)=ln(3)\\
y+3= \frac{ln(3)}{ln(4)} =0.7925\\y=0.7925-3=-2.2075
Answer: y = -2.21 (nearest hundredth)
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