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2 years ago

Which is the slope for the equation that is perpendicular to y=-4x+3

Mathematics

1 answer:

zzz [600]2 years ago

4 0

Answer:

$\frac{1}{4}$

Step-by-step explanation:

The equation for a line is y=mx + b where m represents the slope

If a line is perpendicular to another line, it's slope is the negative reciprocal of the other line's slope.

The reciprocal of -4 is $-\frac{1}{4}$

And the negative of that would be $\frac{1}{4}$

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Step-by-step explanation:

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alukav5142 [94]

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$= \dfrac{7 \times 5}{4 \times 5} - \dfrac{3 \times 10}{2 \times 10} - \dfrac{2 \times 4}{5 \times 4}$

$= \dfrac{35}{20} - \dfrac{30}{20} - \dfrac{8}{20}$

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---------------------------------------------------------------

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$= -\dfrac{5}{16} + \dfrac{3 \times 4}{4 \times 4} + \dfrac{1 \times 2}{8 \times 2}$

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$= -\dfrac{2}{12}$

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---------------------------------------------------------------

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$= \dfrac{2}{9} - \dfrac{1}{6} - \dfrac{2}{3}$

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