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Roman55 [17]
3 years ago
11

Need help on all three questions please?

Mathematics
1 answer:
Delicious77 [7]3 years ago
8 0

Answer:

Df=11

<b's complement must be 10°

<d's supplement must be 100°

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Solve: 1/2x - 7 = 1/3 (x-12)
MArishka [77]

x = 18

Have a merry Christmas!

3 0
3 years ago
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Given △DEF, which is not equal to cos(F)? sin(F). sin(D). tan(F). cos(D)
valentina_108 [34]

Answer: The correct option is tan(F).

Explanation:

In the given figure the triangle is a right angle triangle because \angle E=90^{\circ}.

It is also given that DE=EF=5 and DF=5\sqrt{2}.

Since it is an isosceles right angle triangle, therefore the value of perpendicular and base is same for both angles D and F, which is 5.

\cos (F)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(F) is \frac{1}{\sqrt{2}}.

\sin (F)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(F) is \frac{1}{\sqrt{2}}.

\sin (D)=\frac{Perpendicular}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of sin(D) is \frac{1}{\sqrt{2}}.

\tan (F)=\frac{Perpendicular}{Base}=\frac{5}{5} =1

The value of tan(F) is 1. Which is not equal to \frac{1}{\sqrt{2}}.

\cos (D)=\frac{Base}{Hypotenuse} =\frac{5}{5\sqrt{2}} =\frac{1}{\sqrt{2}}

The value of cos(D) is \frac{1}{\sqrt{2}}.

Therefore, the value of tan(F) is not equal to the value of cos(F), so the correct option is third.

3 0
4 years ago
Read 2 more answers
Solve the system of equations.
lord [1]

Answer is B.) (-3,-3) and (2,7)

3 0
3 years ago
I need help with this queston
ozzi

Answer:

<h2>(55/27, 32/9)</h2>

Step-by-step explanation:

The system of equations is

3x+7y=31 \\3x-2y=-1

The first step is to arrange like terms in colums, which is already done.

Then, we need to multiply a number by one equation in such way where we get opposite like terms. Notice that we need to multiply the first equation by -1

-3x-7y=-31\\3x-2y=-1

Then, we sum equations to obtain the value of one variable.

0-9y=-32\\y=\frac{-32}{-9}\\ y=\frac{32}{9}

Now, we use this value to find the second variable

3x-2y=-1\\3x-2(\frac{32}{9} )=-1\\3x=-1+\frac{64}{9}\\ 3x=\frac{-9+64}{9}\\ 3x=\frac{55}{9}\\ x=\frac{55}{27}

Therefore, the solution is (55/27, 32/9).

(The image attached shows the graphic solution)

5 0
3 years ago
I dont know if im right or not but i think its G can anyone help?
AnnyKZ [126]
You’re right it’s G because when you are going to your righ it’s goin by 7 n same on the left side
6 0
3 years ago
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