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diamong [38]
2 years ago
14

49. Sketch the graph of the polar equation. r=3 \cos \theta

Mathematics
1 answer:
liraira [26]2 years ago
4 0

Answer:

1.5

Step-by-step explanation:

r=2Rcosθ

(x-1.5)² y²=2.25

The centre of the circle is (1.5 , 0) The radius is 1.5

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If rs =3x + 1, st = 2x- 2 ,and rt = 64,find the value of x
stealth61 [152]
             rs + st = rt     Plug in the values
3x + 1 + 2x - 2 = 64   Combine like terms (1 and -2)
       3x -1 + 2x = 64   Combine like terms (3x and 2x)
            -1 + 5x = 64   Add 1 to both sides
                  5x = 65   Divide both sides by 5
                    x = 13
3 0
3 years ago
5 ordered pairs of y=2x+5 please help its due tomorrow
dybincka [34]
(0,5) (-3, -1) (1, 7) (2, 9) (-5, -5)
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2 years ago
Determine whether the forces in the pair are pulling at right angles to each other.
prohojiy [21]

Answer:

C) 3.0

Step-by-step explanation:

Let the length of the other side be x.

Using Pythagoras theorem for right-angled triangle,

4.2^2=2.9^2+x^2

or,x^2=4.2^2-2.9^2

or,x^2=9.23

or,x=√9.23=3.0 units

7 0
3 years ago
HELP ME QUICK PLEASEE!!
Lena [83]

Answer:

  A) is a function

  B) f(x) is greater

  C) x = 12

Step-by-step explanation:

A) Yes, the relation is a function.

A function has a unique input value for each output value. There are no repeated x-values, so this relation is a function.

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B) The table says y=6 for x=6.

  f(6) = 2(6)+16 = 28

f(x) has a greater value for x=6.

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C) Substituting the given information, we have ...

  40 = 2x +16

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The value of x is 12 when f(x) is 40.

3 0
3 years ago
Write the following series in sigma notation.<br> 7 + 16 + 25 +34 +43 +52 + 61
Solnce55 [7]

The series 7 + 16 + 25 +34 +43 +52 + 61 is an illusration of arithmetic series

The sigma notation of the series is: \sum\limits^7_{n=1} {9n - 2}

<h3>How to write the series in sigma notation?</h3>

The series is given as:

7 + 16 + 25 +34 +43 +52 + 61

The above series is an arithmetic series, with the following parameters

  • First term, a = 7
  • Common difference, d = 9
  • Number of terms, n = 7

Start by calculating the nth term using:

a(n) = a + (n - 1) * d

This gives

a(n) = 7 + (n - 1) * 9

Evaluate the product

a(n) = 7  - 9 + 9n

Evaluate the difference

a(n) = 9n - 2

So, the sigma notation is:

\sum\limits^7_{n=1} {9n - 2}

Read more about arithmetic series at:

brainly.com/question/6561461

3 0
2 years ago
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