Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank
boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time
boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet
The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates
(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x
1100x + x^2 = 1400x + 700000
x^2-300x -700000 = 0 quadratic formula yields x = 1000
One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m
I can't see the problem so repost it and tag me in it
Answer:
3/8
Step-by-step explanation:
3/4 x 1/2 = 3/8
Answer:
10
Step-by-step explanation:
By Pythagoras' Theorem:
16 + r = √(24^2 + r^2)
(16 + r)^2 = 24^2 + r^2
256 + 32r + r^2 = 576 + r^2
32r = 320
r = 10
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