Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
median 6.5
mean 6.166
range 6
Step-by-step explanation:
Answer: 
Step-by-step explanation:
<u>Given information</u>
Paid = $15.00 / hour
Paid (Last 4 hours) = Doubled the usual pay rate
Total hour = 12 hours
<u>Given expression</u>
Wage = Pay rate × hours except for the last 4 hours + Double Pay rate × 4 hours
<u>Substitute values into the expression</u>
Wage = (15) × (12 - 4) + (15 × 2) × (4)
<u />
<u>Simplify values in the parenthesis</u>
Wage = 15 × 8 + 30 × 4
<u>Simplify by multiplication</u>
Wage = 120 + 120
<u>Simplify by addition</u>
Hope this helps!! :)
Please let me know if you have any questions
(4/9) divided by (7/12) = 4/9 * 12/7 = 48/63 = 16/21
