Answer: 6 large frames and 12 small frames
Step-by-step explanation:
We define the following:
x = number of large frames
y = number of small frames
Make the following equations:
x + y = 18
19x + 9y = 222
Use system of equations to solve. We find the value of x first.
y = 18 - x
⇒ 19x + 9(18 - x) = 222
⇒ 19x + 162 - 9x = 222
⇒ 10x + 162 = 222
⇒ 10x = 60
⇒ x = 6
Find value of y:
6 + y = 18
y = 12
∴ 6 large frames and 12 small frames were purchased.
Answer:


The curve (B) matches the graph of y=x²-4x.

Answer:
(4, 2.5)
Step-by-step explanation:
Steps to solve:
15 + 2a = 35
~Subtract 15 to both sides
2a = 20
~Divide 2 to both sides
a = 10
Best of Luck!
The maximum height the ball achieves before landing is 682.276 meters at t = 0.
<h3>What are maxima and minima?</h3>
Maxima and minima of a function are the extreme within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.
We have a function:
h(t) = -4.9t² + 682.276
Which represents the ball's height h at time t seconds.
To find the maximum height first find the first derivative of the function and equate it to zero
h'(t) = -9.8t = 0
t = 0
Find second derivative:
h''(t) = -9.8
At t = 0; h''(0) < 0 which means at t = 0 the function will be maximum.
Maximum height at t = 0:
h(0) = 682.276 meters
Thus, the maximum height the ball achieves before landing is 682.276 meters at t = 0.
Learn more about the maxima and minima here:
brainly.com/question/6422517
#SPJ1