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julia-pushkina [17]
2 years ago
9

Can someone help me with this question please?

Mathematics
1 answer:
zheka24 [161]2 years ago
7 0
(1,0) or (2,5) or (3,10)
5-0=5, 10-5=5, and 15-10=5
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I will give a brainlest, i promise, please help me with this.​
valkas [14]

Answer:

1) b and m

2) m∠8=m∠6

3) 160°

4)x=60°

Step-by-step explanation:

1) all straight lines sum to 180°

subtract the angles given from 180°

the other angle for b is 25°, while the other angle for m is 155°

so we can see that the angles for both lines are the same, hence they are parallel.

2) ∠8 should be the same as ∠6, ∠10 should be the same as ∠3, ∠7 same as ∠5 and ∠9 same as ∠4

in the options we are only given '∠8 should be the same as ∠6' as the correct answer, so we take that.

3) from the image we can see that both horizontal lines are parallel to each other, so both angles on the lines should be same, so ∠CET would be (2x-16)°

(2x-16)°+(7x+20)°=180°

we get x=20(nearest whole number)

∠CED=7x+20=7(20)+20=160°

4) since we need to show that they are parallel,

(2x+30)°=(4x-90)°

2x-4x=-90-30

-2x=-120

x=60

we then plug the x value into the two equations, in which we get 150° for both the angles [2(60)+30=4(60)-90] ⇒ (150=150)

I hope u understand it the way I put it.

8 0
2 years ago
Carlos tried to shade all the factors of 30 on the hundred chart. Hundred chart with 1, 2, 3, 5, 6, 10, 15, and 30 shaded. What
Nastasia [14]

Answer:

30 is the wrong one because it is not a factor of 100

30 60 90 120

20 40 60 80 100

Step-by-step explanation:

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2 years ago
A jet, in calm air conditions, travels with velocity vector (389, 389). The wind velocity (in mph) at the plane’s cruising altit
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After thorough researching, if a jet in calm air conditions travels with velocity vector (389, 389) and the wind velocity (in mph) at the plane’s cruising altitude is given by (0, 50), then the plane’s true speed is 600 mph. The correct answer to the following given statement above is with the letter C.
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Answer:

Step-by-step explanation:

o find the unit rate , divide the numerator and denominator of the given rate by the denominator of the given rate.

start with the rate of miles to gallons . then divide , write as a rate.

hope this helps.

where are the following vehicles name

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2 years ago
3(n+5)≥3n+8 Solve for n<br> a.n≥23<br> b. all real numbers<br> c. no solution <br> d. n≥7
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all real numbers are greater than or equal to the equation

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