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3 years ago

ANSWER FAST AND GET ALOT OF POINTS

Mathematics

1 answer:

garik1379 [7]3 years ago

8 0

Answer: A= 163.27 B= all numbers are outliers

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Write an equation in slope-intercept form of the line that passes through (6, -2) and (12, 1)

bogdanovich [222]

Answer:

y= .5x - 5

Step-by-step explanation:

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4 years ago

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Which expression is equivalent to (f + g)(4)?

ddd [48]

(f + g)(x) = f(x) + g(x) therefore (f + g)(4) = f(4) + g(4)

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3 years ago

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(5j - 2q + 2/5) - (4 - 3j - 1/2q)

fenix001 [56]

Answer:

8j - $\frac{3q}{2}$ - $\frac{18}{5}$

Step-by-step explanation:

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5 0

3 years ago

00 PM

Svetllana [295]

Answer:

0.67

Step-by-step explanation:

To solve this we are going to use this lovely equation

P%•X=Y

Y is our end product

X in this case is 45

and P% is our percent

Now let's multiply 4% which becomes .004 by 45 and we get 1.8 which since there isn't 1.8 in American currency that becomes $1.80

We do the same process with the 2.5

0.025•45=1.125

Again not in the American currency so we will round 5 up and now we have $1.13

Now we subtract 1.80-1.13 which gets us 0.67 cents.

Hope I was helpful,

Your friendly neighborhood struggling student

Toodles

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3 years ago

Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of

Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

$\triangle ABC \sim \triangle NMP$