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Nikolay [14]
3 years ago
14

Given:

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0

There are several ways two triangles can be congruent.

\mathbf{\triangle AOK \cong \triangle BOL} are congruent by SAS

In \mathbf{\triangle AOL} and \mathbf{\triangle BOK} (see attachment), we have the following observations

1.\ \mathbf{AO = BO} --- Because O is the midpoint of line segment AB

2.\ \mathbf{\angle AOL = BOK} ---- Because vertical angles are congruent

3.\ \mathbf{LO = KO} --- Because O is the midpoint of line segment KL

Using the SAS (<em>side-angle-side</em>) postulate, we have:

\mathbf{\triangle AOK \cong \triangle BOL} ---- i.e. both triangles are congruent

The above congruence equation is true because:

  1. <em>2 sides of both triangles are congruent</em>
  2. <em>1 angle each of both triangles is equal</em>

Read more about congruence triangles at:

brainly.com/question/20517835

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Answer:

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Step-by-step explanation:

Given:

The expression in radical form is given as:

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We need to express this in fractional exponent form.

We know that,

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Now, clubbing both the properties of square root function, we can rewrite the given expression as:

\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}

So, the given expression in fractional exponents form is a^{\frac{1}{2}}b^{\frac{1}{2}}.

3 0
3 years ago
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MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

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feel free to correct  

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3 years ago
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Answer:

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If the units are different than those given, please state them underneath my answer. I'll get to it as soon as I see your comment.

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hope it helped
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