Answer:
0.25% probability that they are both defective
Step-by-step explanation:
For each computer chip, there are only two possible outcomes. Either they are defective, or they are not. The probability of a computer chip being defective is independent of other chips. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
5% of the computer chips it makes are defective.
This means that
If an inspector chooses two computer chips randomly (meaning they are independent from each other), what is the probability that they are both defective?
This is P(X = 2) when n = 2. So
0.25% probability that they are both defective
Prime numbers have only 2 factors 1 and its number for example:
2, 3, 5, 7, 11, 13, 17, 19, 23
Like this 1*2. Or 3*1
Composite numbers have more than two factors for example :
0, 4, 6, 8, 9, 10, 12, 14 15, 16..
For example 0 has many factors
0 times 3 0times 4
65*1.60=$104
Hope that helps
The answer is 7!
The number In front of the variable is always the coefficient.
Step-by-step explanation:
b =-4 (y-intercept)
x =0
m = 0 (the line doesn't have a slope)
y = mx + c
y = 0(0) + (-4)
y = - 4