Is this correct? If not please tell me what is. If it is correct just say 'yep! it's correct!' or something like that- Thanks :)

11. Write 850 as the product of its prime factors. A. 17 × 50 B. 5 × 10 × 17 C. 10 × 85 D. 2 × 5 × 5 × 17

RideAnS [48]

D. 2 x 5 x 5 x 17

hope this helps

4 0

3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

<em>See attachment for result of 1-VarStats</em>

8 0

3 years ago

What is the resulting equation when the expression for y in the second equation is substituted into the first equation? 3x y = 1

Natali5045456 [20]

After putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

GIven:

The equations are:

$3x + y = 1\\
y = 6 - 4x$

It is required to put the value of y from second equation to the first equation.

<h3>How to solve equations?</h3>

The value of y from the second equation is,

$
y = 6 - 4x$

Now, put this value of y in the first equation as,

$3x + y = 1\\
3x+(6 - 4x)=1\\
3x+6-4x=1\\
-x=-5\\
x=5$

Therefore, after putting the value of y from the second equation to the first equation, the resultant equation is $x=5$ .

For more details about equations, refer to the link:

brainly.com/question/2263981

8 0

2 years ago

Will give brainliest!

Ghella [55]

D tethetjwtjwtjwhwtjwtj

3 0

3 years ago

Describe the motion of a particle with position (x, y) as t varies in the given interval. (For each answer, enter an ordered pai

DerKrebs [107]

Answer:

The motion of the particle describes an ellipse.

Step-by-step explanation:

The characteristics of the motion of the particle is derived by eliminating $t$ in the parametric expressions. Since both expressions are based on trigonometric functions, we proceed to use the following trigonometric identity: