G(-8)=(-8)^2-5(-8)
=64+40
g(-8)=104
k=-3 Try using a technique DLAM, Distributive property,like terms, Add/subtract (if its positive,make it a negative) and variables (divide your result from the last step.)
Answer:
30th term is
9(30+3) =270+27=297
to find the first term which is larger than 100
9(n+3) =100
9n=100-27
9n=73
n=73÷9
=8.1
so when n is>8.1 all the terms will be larger than 100 and the first term will be 9 since n can't be fraction as it's an ordinary number
so it's 9th
9(9+3) =81+27=108
the first four terms are
9(1+3) =36
9(2+3) =45
9(3+3) =81
9(4+3) =63
Step-by-step explanation:
n(n-1)
the first four terms are
1(1-1) =0
2(2-1) =2
3(3-1) =6
4(4-1) =12
the 10th term is 10(10-1) =90
to find weather 51 is a term or not
n(n-1) =51
n^2-n-51=0
1-4×1×-51=1+204=205
so it's roots will be fraction
so it's not from its terms because n will
be fraction
to find the term 182
n(n-1) =182
n^2-n-182=0
(n-14) (n+13)=0
so it's the term 14th because n can't be negative
<u>Answer:</u>
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<u>6</u>
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<u>Step-by-step explanation:</u>
<u></u>
<u>zx + 2 is the same as z*x+2</u>
<u></u>
<u>since you are given the value of both z and x, you can just substitute the values into the equation and solve.</u>
<u></u>
<u>(z) * (x) + 2 = ?</u>
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<u>(2) * (2) + 2 = ?</u>
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<u>4 + 2 = ?</u>
<u></u>
<u>-FrxziteThelxoser- If I helped you with your work, mind giving me brainliest?</u>
