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Kipish [7]
2 years ago
11

HELP ME NOW 100 POINTS PLS

Mathematics
2 answers:
Phantasy [73]2 years ago
6 0

Answer:

25 = 5x + 4 \\  \\ 5x = 25 - 4 \\  \\ 5 x = 21 \\  \\ x =  \frac{21}{5}  \\  \\ x = 4.2

it's was helpful to you

stira [4]2 years ago
6 0

Step-by-step explanation:

25=5x+4

-4 -4

21=5x

21/5=5x/5

4.2=x

You might be interested in
The sum of two numbers is 65 and the difference of those two numbers is -18
joja [24]

Answer:

41.5

23.5

Step-by-step explanation:

Let's start by calling the two numbers we are looking for x and y.

The sum of x and y is 65. In other words, x plus y equals 65 and can be written as equation A:

x + y = 65

The difference between x and y is -18. In other words, x minus y equals -18 and can be written as equation B:

x - y = -18

Now solve equation B for x to get the revised equation B:

x = -18 + y

Then substitute x in equation A from the revised equation B and then solve for y:

x + y = 65

-18+y+y=65

-18 + 2y = 65

2y = 83

y = 41.5

Now we know y is 41.5. Which means that we can substitute y for 41.5 in equation A and solve for x:

x + y = 65

x + 41.5= 65

X = 23.5

DIfference : 23.5 - 41.5 = 18

Sum: 41.5 +23.5 = 65

Hence, The two number are 23.5 and 41.5

[RevyBreeze]

4 0
2 years ago
What is the answer to 2<0.75v<4.5
Vlad [161]
I hope this helps you

3 0
2 years ago
Read 2 more answers
What is the measure of the angle of rotation for the polygon?
m_a_m_a [10]

Answer:

360 degrees divided by that order

7 0
2 years ago
I need help with both of these problems
GREYUIT [131]
The first question is D because if the
y-intercept is 1 then every point moves down three units.

The second question is J because a vertical line is not a function so it can’t be a linear function.
8 0
3 years ago
Please help! The volume of an inflated spherical water balloon is 121,500 pi millimeters to the third. What is the radius of the
irga5000 [103]

Answer:

The radius of the inflated spherical balloon  is 45 millimeters.

Step-by-step explanation:

Volume of the spherical water balloon = 121,500 pi  cubic millimeters

Let the radius of the balloon = r

Now, Volume of a Sphere = \frac{4}{3} \pi r^{3}

⇒\frac{4}{3} \pi r^{3}  = 121,500 \pi

On solving for the value of r, we get:

r^{3}  = \frac{121,500\times 3}{4}   = 91125\\ \implies  r  = \sqrt[3]{91125}

or, r  = 45 millimeter

Hence, the radius of the inflated spherical balloon  is 45 millimeters.

5 0
3 years ago
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